A packet dropped from a balloon which is going upwards with the velocity $12 m / s$ , the velocity of the packet after $2$ seconds will be :

- 12 m / s

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12 m / s

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- 7.6 m / s

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7.6 m / s

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Solution

The correct option is C $- 7.6 m / s$
Given,

$u = 12 m / s$

$t = 2 s e c$

$g = - 9.8 m s^{2}$

1st equation of motion,

$v = u + g t$

$v = 12 - 9.8 \times 2 = 12 - 19.6$

$v = - 7.6 m / s$

The correct option is C.

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A packet dropped from a balloon which is going upwards with the velocity 12m/s, the velocity of the packet after 2 seconds will be :

The correct option is C −7.6m/sGiven,u=12m/st=2secg=−9.8ms21st equation of motion,v=u+gtv=12−9.8×2=12−19.6v=−7.6m/sThe correct option is C.

A packet dropped from a balloon which is going upwards with the velocity $12 m / s$ , the velocity of the packet after $2$ seconds will be :

The correct option is C $- 7.6 m / s$
Given,

$u = 12 m / s$

$t = 2 s e c$

$g = - 9.8 m s^{2}$

1st equation of motion,

$v = u + g t$

$v = 12 - 9.8 \times 2 = 12 - 19.6$

$v = - 7.6 m / s$

The correct option is C.