Question

A pair of dice is thrown once. The probability that the sum of the outcomes is less than 11 is:

• A. 29/36
• B. 7/36
• C. 11/12
• D. 1/6

Answer 1

Answer: (C)

11/12

There are a total of 36 outcomes when two dice are thrown. All the pairs are Favorable outcomes except (6,6), (6,5), and (5,6) whose sum is equal to or more than 11.
Therefore $36-3=33$ outcomes that are favorable.

Hence,
$P(sum<11)$ $=$ $\frac{33}{36}=\frac{11}{12}$