Question

A pair of disc rolled $24times$. A person wins by not getting a pair of $6^{\prime }s$ on any of the $24$ rolls. What is the probability of his wining?

Answer 1

Dice is rolled $24$ times

$\therefore$. of outermost $=6^{24}=4.74\times {10}^{18}$

No. of times $6^{\prime }s$ pair arrives $=24$

$\therefore$ Probability of winning $=\frac{4.74\times {10}^{18}-24}{4.74\times {10}^{18}}$

$=0.99$

$=\frac{99}{100}$ Ans