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Question

A pair of fair dice is tossed repeatedly until a sum of four or an odd sum appears. Then the probability that a sum of four appear first is

A
13
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B
25
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C
38
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D
17
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Solution

The correct option is D 17
A pair of fair dice is tossed repeatedly therefore probability of
P(sum of four)=336=112,
P(odd sum )=1836=12
P(neither sum of four nor odd sum )=111212=512
Required probabilityP=112+512×112+(512)2112+....
P=1121512=17

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