Question

A pale blue liquid which is obtained by reacting equimolar mixture of two gases at -${30}^{o}C$ is :

• A. $N_2{O}_3$
• B. $N_{2}O$
• C. $N_2{O}_4$
• D. $N_2{O}_5$

Answer 1

The correct option is A $N_2{O}_3$

$N{H}_{4}N{O}_3\to N_{2}O+2H_{2}O$

$N\equiv N\to O$ (sp, linear and polar molecule)

$3Cu+8HN{O}_3\to 3Cu(N{O}_3{)}_2+2NO$

$NO+N{O}_2\stackrel{LowT}{\underset{-{30}^{o}C}{\rightleftharpoons }}{N}_2{O}_3$ (pale blue)

Hence, option A is correct.