Question

A panda with a mass of $90.0kg$ lies without moving on a ramp that is inclined at ${25.0}^o$.
What is the coefficient of static frictional force between the ramp and the panda?

• A. $0.25$
• B. $0.423$
• C. $0.466$
• D. $372$
• E. The coefficient of static friction cannot be determined with the information given

Answer 1

The correct option is C $0.466$

Given : $\theta ={25}^o$

As the panda is in equilibrium, thus net force on the panda is zero.

$\therefore$ $N=mgcos\theta$ $⟹f=\mu N=\mu mg$ $cos\theta$

Also $mgsin\theta =f=\mu mgcos\theta$

$⟹$ $\mu =tan\theta =tan{25}^o=0.466$