Question

A paper is in the form of a rectangle ABCD in which AB = 20 cm and BC = 14 cm. A semi-circular portion with BC as the diameter is cut off. Find the area of the remaining part.$(Use\pi =\frac{22}{7})$.

• A. $200c{m}^2$
• B. $203c{m}^2$
• C. $209c{m}^2$
• D. $230c{m}^2$

Answer 1

The correct option is B $203c{m}^2$

Area of remaining part = Area of rectangle - Area of semicircle
$=20\times 14-\frac{22\times 7\times 7}{7\times 2}$
$=280-77$
Hence, area of remaining part =$209c{m}^2$