A paper is in the form of a rectangle ABCD where AB = 22 cm and BC = 14 cm. A semicircle portion with BC as diameter is cut off. Find the area of the remaining paper in cm2.
231
Area of rectangle = 22×14=308cm2
Area of semicircle
= 12×227×(7)2=77cm2
Required area = [Area of rectangle - Area of semicircle]
= 308 – 77 = 231cm2