Question

A paper is in the form of a rectangle ABCD where AB = 22 cm and BC = 14 cm. A semicircle portion with BC as diameter is cut off. Find the area of the remaining paper in $c{m}^2$.

• A. 221
• B. 210
• C. 231
• D. 240

Answer 1

The correct option is C

231

Area of rectangle = $22\times 14=308c{m}^2$
Area of semicircle
= $\frac{1}{2}\times \frac{22}{7}\times (7{)}^2=77c{m}^2$
Required area = [Area of rectangle - Area of semicircle]
= 308 – 77 = $231c{m}^2$