Question

A paper is marked out of $180$. Minimum requirement for a pass is $45\%$. What is the highest mark that can be obtained by a student who fails?

Answer 1

Given:

Maximum Marks $=180$

Minimum percentage required to pass $=45\%$

Now,

$45\%$ of $180$ $=180\times 45\%$

$$\begin{gathered} =180\times \frac{45}{100} \\ =\frac{180\times 45}{100} \\ =\frac{8100}{100} \\ =81 \end{gathered}$$

Hence, passing marks $=81$.

We know that highest marks that can be obtained by a student who fails is $1$ mark less than the passing marks.

So, the highest mark obtained by a student who fails $=81-1=80$.

Hence, the highest mark is $80$ that can be obtained by a student who fails.