A paper weight of R.I $=$ 1.5 is hemispherical with radius 3 cm. It is kept on a printed page, the printed letter will appear at a height of $- ------- -$ from the bottom when viewed vertically :

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1 cm

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2 cm

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1.21 cm

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Solution

The correct option is B 1 cm
The refractive index is defines as,
$μ = \frac{t_{r e a l}}{t_{a p p a r e n t}}$

Now, the shift in image is given by,

$δ t = t_{r e a l} - t_{a p p a r e n t}$

Substituting the values,
$δ t = 3 - \frac{3}{1.5} = 3 - 2 = 1$

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A paper weight of R.I = 1.5 is hemispherical with radius 3 cm. It is kept on a printed page, the printed letter will appear at a height of –––––––––from the bottom when viewed vertically :

The correct option is B 1 cmThe refractive index is defines as,μ=trealtapparentNow, the shift in image is given by,δt=treal−tapparentSubstituting the values,δt=3−31.5=3−2=1

A paper weight of R.I $=$ 1.5 is hemispherical with radius 3 cm. It is kept on a printed page, the printed letter will appear at a height of $- ------- -$ from the bottom when viewed vertically :

The correct option is B 1 cm
The refractive index is defines as,
$μ = \frac{t_{r e a l}}{t_{a p p a r e n t}}$

Now, the shift in image is given by,

$δ t = t_{r e a l} - t_{a p p a r e n t}$

Substituting the values,
$δ t = 3 - \frac{3}{1.5} = 3 - 2 = 1$