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Question

A parabola is drawn with focus at (3,4) and vertex at the focus of another parabola y212x4y+4=0. Then equation of the parabola is

A
x26x8y+25=0
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B
y28x4y+28=0
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C
x26x+8y25=0
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D
x24x8y+28=0
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Solution

The correct option is A x26x8y+25=0
y212x4y+4=0

(y2)2=12x

Vertex is (0,2) and a=3

The focus of parabola is (3,2)

Hence the vertex of required parabola is (3,2) and focus is (3,4), then

a=0+22=2

So required parabola is (x3)2=4(2)(y2)

x26x8y+25=0

Hence, option 'A' is correct.

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