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Question

A parabolic vertical curve is being designed to join a road of grade +5 % with a road of grade -3 %. The length of the vertical curve is 400 m measured along the horizontal. The vertical point of curvature VPC is located on the road of grade +5 %. The difference in height between VPC and vertical point of intersection (VPI) (in m, round of to the nearest integer) is


  1. 10

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Solution

The correct option is A 10

n1=0.05

n2=0.03

L=400 m

The difference in the height between VPC and VPI,
y=n1×L2

=0.05×4002

=10 m


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