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Question

A parabolic vertical curve is set out connecting a + 0.7% grade to a -0.6% grade. The chainage and RL of the point of intersection are 1000 m and 250 m respectively. The admissible rate of change of grade is 0.05% per 20 m. The chainage (in m) of the tangent points will be

A
600 and 1400
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B
740 and 1260
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C
700 and 1300
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D
650 and 1350
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Solution

The correct option is B 740 and 1260
Length of vertical curve,

=0.7(0.6)(0.05/20)=520 m

Length of curve on either side of the apex,

=5202=260 m

Chainage of first tangent point = 1000-260 = 740 m

Chainage of second tangent point = 1000 + 260 = 1260 m

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