A parachute of weight w strikes the ground with his legs fixed and comes to rest with an upward acceleration of magnitude 3g. Force exerted on him by ground during landing is :
A
4w
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B
3w
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C
2w
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D
w
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Solution
The correct option is A4w According to Newton's 3rd law, the force exerted on the man by the ground and the force exerted on the ground by the man is equal and opposite. so from FBD, F=3mg+w=3w+w=4w (Here, w=mg)