Question

A parachutist after bailing out falls $50\text{m}$ without friction. When parachute opens, it decelerates at $2{\text{m/s}}^2$. He reaches the ground with a speed of $3\text{m/s}$. At what height, did he bail out ?

• A. $182\text{m}$
• B. $91\text{m}$
• C. $111\text{m}$
• D. $293\text{m}$

Answer 1

The correct option is D $293\text{m}$

$\text{v}=\sqrt{2\text{gh}}=\sqrt{2\times 9.8\times 50}=14\sqrt{5}$

$\text{S}=\frac{{\text{v}}^2-{\text{u}}^2}{2\times 2}=\frac{3^2-980}{4}\approx 243\text{m}$

Initially he has fallen from $50\text{m}$.

$\therefore$ Total height from where he bailed out $=244+50=293\text{m}$