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Question

A paralle plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates. The work done by the capacitor on the slab is

A
692 pJ
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B
508 pJ
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C
560 pJ
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D
600 pJ
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Solution

The correct option is B 508 pJ
Work done by capacitor on the slab can be written as
W=ΔU
W=(1)(CV)22KC(CV)22C
W=(CV)22CK1K
W=508 J.

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