A parallel beam of diameter d is incident on air-glass interface as shown in figure. The diameter of refracted light beam is : (d=3mm,θ=45o and nglassnair=32)
A
√12mm
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B
√14mm
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C
√6mm
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D
4.5mm
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Solution
The correct option is B√14mm We use the formula for refractive index, μ=sinisinr This, gives, sin r = 1√232 Thus, sinr=23√2 Thus, cosr=√73 Now, applying simple geometry arguments, d′=√2dcosr Hence, d' = √14