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Minimum Deviation

A parallel be...

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A parallel beam of light is incident on a face of a prism of refracting angle 60^° . Find the refractive index of the prism if the angle of minimum deviation is 40^° . What is the new angle ofminimum deviation if the prism is immersed in water of refractive index 1.33?

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A prism is made of glass of unknown refractive index. A parallel beam of light is incident on a face of the prism. The angle of minimum deviation is measured to be 40°. What is the refractive index of the material of the prism? The refracting angle of the prism is 60°. If the prism is placed in water (refractive index 1.33), predict the new angle of minimum deviation of a parallel beam of light.

Q. A prism has minimum angle of deviation at

40^{\circ} .

Refracting angle of prism is

60^{\circ} .

If the prism is placed in water of refractive index is

1.33,

what will be new minimum angle of deviation?

Q. A prism of refractive index 1.53 is placed in water of refractive index 1.33. If the angle of the prism is 60

^{o}

, calculate the angle of minimum deviation in water.

Q. A glass prism with a refracting angle of

60^{\circ}

has a refractive index

1.52

for red light. A parallel beam of white light is incident on one face of the prism at an angle of incidence, which gives minimum deviation for red light. Find the angle of minimum deviation for red light.
[Given:

sin (50^{\circ}) = 0.760

]

Q. A prism having refractive index

μ = 1.53

is placed in water having refractive index

μ = 1.33

. If the angle of prism is

60^{\circ}

. Calculate the angle of minimum deviation in water.

(sin {35.1}^{\circ} = 0.575)

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