A parallel beam of light is incident on a thin prism of angle $\frac{4}{π}$ degree. Refractive index of prism is 1.5. A convex lens of focal length 60 cm is placed at distance of 80 cm from prism, then y-coordinate of point where light converges in cm is (Round the answer to two digits after the decimal point.)

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Solution

$A = \frac{4}{π} d e g = \frac{1}{45} r a d$
$δ = (μ - 1) A$

$δ = \frac{y}{60}$

$\frac{y}{60} = (1.5 - 1) \frac{1}{45}$

$y = \frac{2}{3} c m$

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A=4πdeg=145rad δ=(μ−1)A δ=y60 y60=(1.5−1)145 y=23 cm

$A = \frac{4}{π} d e g = \frac{1}{45} r a d$
$δ = (μ - 1) A$

$δ = \frac{y}{60}$

$\frac{y}{60} = (1.5 - 1) \frac{1}{45}$

$y = \frac{2}{3} c m$