CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A parallel beam of light is incident on the system of two convex lenses of focal lengths f1=20 cm and f2=10 cm. What should be the distance between the two lenses so that rays after refraction from both the lenses pass undeviated?


A
60 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
30 cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
90 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
40 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 30 cm
Given that,
Focus length of lens 1, f1=20 cm
Focus length of lens 2, f2=10 cm

Let image due to lens 1 is formed at I1, so distance between lens 1 and I1 is f1.
For the ray to go undeviated the image formed by lens 1 should lie exactly at the focus of lens 2. Now I1 acts as object for lens 2. Since I1 lies at the focus of lens 2, the ray after refraction becomes parallel and hence goes undeviated.
So, the distance between the lenses =f1+f2=30 cm

Why this question?This question checks the basic rule of image formation i.e.Rays parallel to the principle axis meets at focus andthe converse of this rule.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Focus of a concave lens_tackle
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon