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Question

A parallel beam of light of 500nm falls on a narrow slit and the resulting diffraction pattern is observed on a screen 1m away. It is observed that the first minimum is at a distance of 2.5mm from the centre of the screen. Calculate the width of the slit.


Solution

The distance of the nth minimum from the centre of the screen is,      xn=nDλa
Where, D=  distance of the slit from the screen
             λ= wavelength of the light
              a= width of the slit
For first minimum, n=1
Thus,      2.5×103=(1)(1)(500×109)am
                                a=2×104m
                                a=0.2mm

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