Question

A parallel plate air capacitor has a capacitance of $100\mu F$. The plates are at a distance $d$ apart. If a slab of thickness $t(t\le d)$ and dielectric constant $5$ is introduced between the parallel plates, then the capacitance will be

• A. $50\mu F$
• B. $100\mu F$
• C. $200\mu F$
• D. $500\mu F$

Answer 1

The correct option is D $500\mu F$

Capacitance of capacitor with dielectric $C^{\prime }=K{C}_o$

where $C_o$ is the capacitance of parallel plate air capacitor i.e. $C_o=100\mu F$

Also, $K=5$

$⟹C^{\prime }=5\times 100=500\mu F$