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Capacitance of Parallel Plate Capacitor

A parallel-pl...

Question

A parallel-plate air capacitor of capacitance $245 p F$ has a charge of magnitude $0.148 μ C$ on each plate. The plates are $0.328 m m$ apart. What is the potential difference between the plates(in $V$ )?

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Solution

We know that for capacitor, $Q = C V$
The potential between plates is $V = \frac{Q}{C} = \frac{0.148 \times 10^{- 6}}{245 \times 10^{- 12}} = 604 V$

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