Question

A parallel plate capacitor has $1\mu \text{F}$ capacitance. One of its two plates is given $+2\mu \text{C}$ charge and the other plate, $+4\mu \text{C}$ charge. The potential difference developed across the capacitor is,

• A. $5\text{V}$
• B. $1\text{V}$
• C. $2\text{V}$
• D. $3\text{V}$

Answer 1

The correct option is B $1\text{V}$

The final charge distribution on the inner side of capacitor plates will be as shown below.


Now, $V=\frac{Q}{C}$

$=\left(\frac{Q_1-Q_2}{2C}\right)$

$=\left(\frac{4-2}{2\times 1}\right)=1\text{V}$

Hence, $\left(B\right)$ is the correct answer.