Question

A parallel plate capacitor has an electric field of $105$V /m between the plates .If the charge on one of the capacitor plate is 1$\mu$C,then the magnitude of the force on each capacitor plate is :

• A. 0. 1 N
• B. 0. 05 N
• C. 0. 5 N
• D. 0. 01 N

Answer 1

The correct option is B 0. 05 N

Force of attraction between the plates capacitor

$F=\frac{1}{2}Q\left(\frac{Q}{A{ϵ}_0}\right)$

=$\frac{1}{2}QE$

$\frac{1}{2}\times {10}^{-6}\times {10}^5$

$\frac{1}{20}$

$=0.05N$