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Question

A parallel plate capacitor has area of each plate A, the separation between the plates is d. It is charged to a potential V and then disconnected from the battery. The amount of work done in filling the capacitor completely with a dielectric constant k is :


A
12ε0AV2d[11k2]
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B
12V2ε0Akd
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C
12V2ε0Ak2d
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D
12ε0AV2d[11k]
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Solution

The correct option is C 12ε0AV2d[11k]

When dielectric was not filled C=ε0Ad.

It was changed till V Q=ε0AVd.

energy stored E1=12QV=12ε0AV2d

Now when battery is disconnected Q remains constant. When it is filled with dielectric K

We get C=Kε0Ad. as Q is constant

V decreases by k

V1=12Kε0Ad(VK)2=1ε0AV22dk

work done by us=(V2V1)=ε0AV22d(11k)


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