Question

A parallel-plate capacitor having plate area $25c{m}^2$ and separation $1.00mm$ is connected to a battery of $6.0V$ Calculate the charge flown through the battery. How much work has been done by the battery during the process?

Answer 1

The capacitance of a capacitor is given as,

$C=\frac{{\epsilon }_{0}A}{d}$

$=\frac{8.85\times {10}^{-12}\times 25\times {10}^{-4}}{1\times {10}^{-3}}$

$=2.21\times {10}^{-11}F$

The charge on the capacitor is given as,

$Q=CV$

$=2.21\times {10}^{-11}\times 6$

$=1.33\times {10}^{-10}C$

The work done by the battery is given as,

$W=QV$

$=1.33\times {10}^{-10}\times 6$

$=8\times {10}^{-10}J$

Thus, the charge flown by the battery is $1.33\times {10}^{-10}C$ and the work done by the battery during the process is $8\times {10}^{-10}J$.