A parallel plate capacitor is charged. If the plates are pulled apart

The capacitance increases

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The potential difference increases

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The total charge increases

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The charge and potential difference remain the same

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Solution

The correct option is B The potential difference increases
Capacitance of a parallel plate capacitor
C=ε0Ad
A parallel plate capacitor is charged (battery is disconnected) then the plates are pulled apart, the capacitance decreases while the charge remains the same
∵Potentialdifference=ChargeCapacitance
∴ potential difference increases

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