A parallel plate capacitor is charged to a certain voltage. Now, if the dielectric material (with dielectric constant k) is removed then the
A
capacitance increases by a factor of k
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B
electric field reduces by a factor k
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C
voltage across the capacitor decreases by a factor k
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D
none of these
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Solution
The correct option is D none of these As the capacitor is charged by using cell so potential as well as filed between the plates become constant. For removing dielectric the capacitance becomes C/k. Thus capacitance decreases by a factor of k.