Question

A parallel plate capacitor is made by placing n equally spaced plates connected alternatively. If the capacitance between any two adjacent plates is C then the resultant capacitance is:

• A. nC
• B. $\frac{C}{n}$
• C. (n + 1)C
• D. (n- 1)C

Answer 1

Answer: (D)

(n- 1)C

Above combination will be parallel,

When $n$ equally spaced plates are connected alternatively, $(n-1)$ capacitors, each of capacity $C$ are formed. As they are joined in parallel
$\therefore$ $C_{eq}=(n-1)C$