Question

A parallel plate capacitor of $20\mu \text{F}$ is connected to a $1\text{V}$ battery. The net charge on this capacitor is

• A. $20\mu \text{C}$
• B. $2\mu \text{C}$
• C. zero
• D. $10\mu \text{C}$

Answer 1

The correct option is C zero

Given:

$C=20\mu \text{F};V=1\text{V}$

$\therefore Q=\frac{C}{V}=\frac{20\mu \text{F}}{1\text{V}}=20\mu \text{C}$

Well, the magnitude of charge on the positive and negative plates of this capacitor is $20\mu \text{C}$ but of opposite nature. This means that the net charge will be $(+20\mu \text{C}-20\mu \text{C}=0)$.

That is why the correct option in this case is $\left(c\right)$.