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Power in an AC Circuit

A parallel pl...

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A parallel plate capacitor of capacitance 100 microfarad is connected to a power supply of 200V. A di-electric slab of dielectric constant 5 is now inserted into gap. The work done by the supply during this process is?

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Q. A parallel plate capacitor of capacitance

100 μ F

is connected to a power supply of

200 V

. A dielectric slab of dielectric constant

5

is now inserted into the gap between the plates. The workdone by power supply will be:

Q. A parallel-plate capacitor having plate area 400 cm² and separation between the plates 1⋅0 mm is connected to a power supply of 100 V. A dielectric slab of thickness 0⋅5 mm and dielectric constant 5⋅0 is inserted into the gap. (a) Find the increase in electrostatic energy. (b) If the power supply is now disconnected and the dielectric slab is taken out, find the further increase in energy. (c) Why does the energy increase in inserting the slab as well as in taking it out?

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