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Standard X
Physics
Turns Ratio
A parallel pl...
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A parallel plate capacitor of capacitance 100microfarad is connected to a power supply of 200volt. A dielectric slab of dielectric constant 5 is now inserted into gap. Work done by supply during this process?
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Q.
A parallel plate capacitor of capacitance
100
μ
F
is connected to a power supply of
200
V
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5
is now inserted into the gap between the plates. The workdone by power supply will be:
Q.
A parallel-plate capacitor having plate area 400 cm
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and separation between the plates 1⋅0 mm is connected to a power supply of 100 V. A dielectric slab of thickness 0⋅5 mm and dielectric constant 5⋅0 is inserted into the gap. (a) Find the increase in electrostatic energy. (b) If the power supply is now disconnected and the dielectric slab is taken out, find the further increase in energy. (c) Why does the energy increase in inserting the slab as well as in taking it out?
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and it is charged to
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A parallel-plate capacitor is connected across a battery. Now, keeping the battery connected, a dielectric slab is inserted between the plates. In this process,
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