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Question

A parallel plate capacitor of capacitance 20μF is being charged by a voltage source whose potential is changing at the rate of 3Vs1. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively :
  1. 60μA,0
  2. 0,0
  3. 0,60μA
  4. 60μA,60μA


Solution

The correct option is D 60μA,60μA
Given, capacitance of capacitor 
C=20μF=20×106F
Rate of change of potential (dVdt)=3Vs
q=CV
or, dqdt=CdVdt
or, iC=20×106×3=60×106A=60μA
As we know that id=ic=60μA
[Alternate solution : we know that id=ic and the displacement current has finite value when potential difference across capacitor is changing]

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