a parallel plate capacitor of capacity C is charged to potential V 1.the energy stored in capacitor when the battery is disconnected and the separation in between plates of capacitor doubled is E1 2. the energy stored in the capacitor when the charging battery is kept connected and the separation between the capacitor plates is doubled is E2 then E1/E2 is 1.4 2.3/2 3.2 4.1/2

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Explain briefly the process of charging a parallel plate capacitor when it is connected across a d.c. battery.

A capacitor of capacitance ‘C’ is charged to ‘V’ volts by a battery. After some time the battery is disconnected and the distance between the plates is doubled. Now a slab of dielectric constant, 1 < k < 2, is introduced to fill the space between the plates. How will the following be affected?

(a) The electric field between the plates of the capacitor

(b) The energy stored in thecapacitor

Justify your answer by writing the necessary expressions

Statement 1 :

A parallel plate capacitor is charged by a battery of voltage

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Statement 2 :

The capacitance of a capacitor increases due to the introduction of a dielectric between the plates.

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