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Question

A parallel plate capacitor with no dielectric between the plates is connected to the constant voltage source. How would capacitance and charge change if the dielectric constant K=2 is inserted between the plates?
(C0 and Q0 are the capacitance and charge of the capacitor before the introduction of the dielectric.)

A
C0/2 and 2Q0
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B
2C0 and Q0/2
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C
C0/2 and Q0/2
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D
2C0 and 2Q0
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Solution

The correct option is D 2C0 and 2Q0
The charge becomes K times the previous charge on the capacitor.

So, Q=KQ0=2Q0

In the presence of the dielectric completely filling the space between the plates, the capacitance will increase by the factor of the dielectric constant of the material.

Thus, C=QVo=KQoVo=KC0=2C0

If the battery remains connected across the capacitor, the voltage will remain the same i.e. equal to the voltage of the source.

Hence, option (d) is correct.
Key concept- Capacitance & charge on a parallel plate capacitor with fully filled dielectric medium.

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