Question

A parallel plate capacitor with plates of area $1m^2$ each, area $t$ a separation of $0.1m$. If the electric field between the plates is $100N/C$, the magnitude of charge each plate is:-
$(Take{\epsilon }_0=8.85\times {10}^{-12}\frac{c^2}{N-m^2})$

• A. $7.85\times {10}^{-10}C$
• B. $6.85\times {10}^{-10}C$
• C. $9.85\times {10}^{-10}C$
• D. $8.85\times {10}^{-10}C$

Answer 1

The correct option is D $8.85\times {10}^{-10}C$

$E=\frac{\sigma }{{\in }_0}=\frac{Q}{A{\in }_0}$
$Q=AE{\in }_0$
$Q=\left(1\right)\left(100\right)(8.85\times {10}^{-12})$
$Q=8.85\times {10}^{-19}C$