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Question

A parallel plate capacitor with square plates is filled with four dielectrics of dielectric constants K1,K2,K3,K4 arranged as shown in the figure. The effective dielectric constant K will be :
1329943_1450eb1ac43f47f393862fada7caddae.png

A
K=(K1+K2)(K3+K4)2(K1+K2+K3+K4)
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B
K=(K1+K2)(K3+K4)(K1+K2+K3+K4)
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C
K=(K1+K4)(K2+K3)2(K1+K2+K3+K4)
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D
K=(K1+K3)(K2+K4)K1+K2+K3+K4
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Solution

The correct option is D K=(K1+K3)(K2+K4)K1+K2+K3+K4

C12=C1C2C1+C2=k10L2×Ld/2.k2[0L2×L]d/2(k1+K2)⎢ ⎢ ⎢0.L2×Ld/2⎥ ⎥ ⎥

C12=k1k2k1+k20L2d

in the same way we get , C34=k3k4k3+k40L2d

Ceq=C12+C34=[k1k2k1+k2+k3k4k3+k4]0L2d

Now if keqk,Ceq=k0L2d

on comparing equation (i) to equation (ii) , we get

keq=k1k2(k3+k4)+k3K4(k1+k2)(k1+k2)(k3+k4)

This does not match with any of the options so probably they have assumed the wrong combination

C13=k10LL2d/2+k30L.L2d/2

=(k1+k3)0L2d

C24=(k2+k4)0L2d

Ceq=C13C24C13C24=(K1+K3)(k2+k4)(k1+k2+k3+k4)0L2d

=k0L2d

k=(k1+k3)(k2+k4)(k1+k2+k3+k4)

1142433_1329943_ans_ae453b0c9530494590a21595716d7403.png

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