1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A parallel-plate condenser of capacitance C is connected to a battery and is charged to potential v. Another condenser of capacity 2C is connected to another battery and is charged to potential 2V. The charging batteries are removed and now the condensers are connected in parallel in such a way that the positive plate of one is connected to the negative plate of another. The final energy of this system is

A
25CV26
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
9CV22
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
3CV22
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
0
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is C 3CV22After connecting the common potential is Vc=C2V2+C1V1C1+C2Vc=4CV−CVC+2C=VNegative sign has come because they are connected in parallel in such a way that the positive plate of one is connected to negative plate of another.The final energy of this system is U=12(2C+C)V2c=32CV2

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Idea of Charge
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program