A parallelogram of area $48 c m^{2}$ is divided into two congruent triangles. If the height of the triangle is 4 cm, find the length of the base of the triangle.

16 cm

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12 cm

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14 cm

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8 cm

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Solution

The correct option is B
12 cm

Area of parallelogram = 2 $\times$ Area of triangle
Area of triangle $= \frac{48 c m^{2}}{2} = 24 c m^{2}$
Area of triangle $= \frac{1}{2} \times b a s e \times h e i g h t$
$24 c m^{2} = \frac{1}{2} \times b a s e \times 4 c m$
base = 12 cm

So, measure of base of the triangle is 12 cm.

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A parallelogram of area $48 c m^{2}$ is divided into two congruent triangles. If the height of the triangle is 4 cm, find the length of base of the triangle.
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A rectangle of area $48 c m^{2}$ is divided into two congruent triangles across its diagonal. Find the sum of the areas of both the triangles.

Q. If a parallelogram having area

48 {cm}^{2}

and height 6 cm is transformed into a triangle with the same base and area as that of the parallelogram, then what is the height of the triangle?

Given: Area of parallelogram = Base $\times$ Height

Statement 1: A diagonal of a parallelogram divides it into two congruent triangles.

Statement 2: Areas of two congruent triangles are exactly equal.

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A parallelogram of area 48 cm2 is divided into two congruent triangles. If the height of the triangle is 4 cm, find the length of the base of the triangle.

The correct option is B 12 cm Area of parallelogram = 2 × Area of triangle Area of triangle =48 cm22=24 cm2 Area of triangle =12×base×height 24 cm2=12×base×4 cm base = 12 cm So, measure of base of the triangle is 12 cm.

A parallelogram of area $48 c m^{2}$ is divided into two congruent triangles. If the height of the triangle is 4 cm, find the length of the base of the triangle.