A parallelogram of area $48 c m^{2}$ is divided into two congruent triangles. If the height of the triangle is 4 cm, find the length of base of the triangle.
[4 MARKS]

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Solution

Process : 3 Marks
Result : 1 Mark

Area of parallelogram = 2(Area of triangle)
Area of triangle = $\frac{48 c m^{2}}{2} = 24 c m^{2}$
Area of triangle = $\frac{1}{2} \times b a s e \times h e i g h t$
$24 c m^{2} = \frac{1}{2} \times b a s e \times 4 c m$
base = 12 cm

So, measure of base of the triangle is 12 cm.

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A parallelogram of area 48 cm2 is divided into two congruent triangles. If the height of the triangle is 4 cm, find the length of base of the triangle. [4 MARKS]

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A parallelogram of area $48 c m^{2}$ is divided into two congruent triangles. If the height of the triangle is 4 cm, find the length of base of the triangle.
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