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Question

A paramagnetic sample shows a net magnetisation of 8A m−1 when placed in an external magnetic field of 0.6T at a temperature of 4K. When the same sample is placed in an external magnetic field of 0.2T at a temperature of 16K, the magnetisation will be.

A
323A m1
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B
23A m1
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C
6A m1
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D
2.4A m1
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Solution

The correct option is B 23A m1
Here, M1=8Am1,B1=0.6T,
T1=4K,B2=0.2T,T2=16K
Then, for paramagnetic materials,
magnetisation(M)=CBT(Curie's law)
Now, in the first case, M1=CB1T1
and in the second case, M2=CB2T2
Dividing equation (i) by (ii), we get
M1M2=B1B2T2T1M1M2=0.60.2×164
8M2=3×4
M2=812=23Am1.

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