Question

A paramagnetic substance, in the form of a cube with sides $1\text{cm}$, has a magnetic dipole moment of $20\times {10}^{-6}\text{J/T}$, when a magnetic intensity of $60\times {10}^3\text{A/m}$ is applied. Its magnetic susceptibility is :

• A. $3.3\times {10}^{-2}$
• B. $4.3\times {10}^{-2}$
• C. $2.3\times {10}^{-2}$
• D. $3.3\times {10}^{-4}$

Answer 1

The correct option is D $3.3\times {10}^{-4}$

Magnetic susceptibility is given by,

$\chi =\frac{I}{H}$

$\text{where,}I=\frac{\text{Magnetic moment}}{\text{Volume}}=\frac{20\times {10}^{-6}}{({10}^{-2}{)}^3}$

$=20{\text{A/m}}^2$

$\therefore \chi =\frac{20}{60\times {10}^3}=3.3\times {10}^{-4}$

Hence, $\left(D\right)$ is the correct answer.