A paramagnetic substance of susceptibility 3 - 10-4 is placed in a magnetic field of 4 - 10-4 Am -1- Then the Intensity of magnetization in the units of Am -1 isA- 14 - 10-8B- 12 - 10-8- 0-75 - 10-8D- 1-33 - 108

The correct option is B 12×10^ 8 X=3×10^ 4 H = 4 ×10^ 4 X = M/H⇒ M = XH=12×10^ 8 ...

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Standard XII

Physics

Magnetic Intensity

A paramagneti...

Question

A paramagnetic substance of susceptibility $3 \times 10^{- 4}$ is placed in a magnetic field of $4 \times 10^{- 4} A m^{- 1}$ . Then the Intensity of magnetization in the units of $A m^{- 1}$ is

$14 \times 10^{- 8}$

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$12 \times 10^{- 8}$

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$0.75 \times 10^{- 8}$

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$1.33 \times 10^{8}$

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Solution

The correct option is B
$12 \times 10^{- 8}$

$X = 3 \times 10^{- 4}$

$H = 4 \times 10^{- 4}$

$X = \frac{M}{H} \Rightarrow M = X H = 12 \times 10^{- 8}$

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A paramagnetic substance of susceptibility 3×10−4 is placed in a magnetic field of 4×10−4Am−1. Then the Intensity of magnetization in the units of Am−1 is

The correct option is B 12×10−8 X=3×10−4 H=4×10−4 X=MH⇒M=XH=12×10−8

A paramagnetic substance of susceptibility $3 \times 10^{- 4}$ is placed in a magnetic field of $4 \times 10^{- 4} A m^{- 1}$ . Then the Intensity of magnetization in the units of $A m^{- 1}$ is

The correct option is B
$12 \times 10^{- 8}$

$X = 3 \times 10^{- 4}$

$H = 4 \times 10^{- 4}$

$X = \frac{M}{H} \Rightarrow M = X H = 12 \times 10^{- 8}$