Question

A parent nuclei (decay constant ${\lambda }_1$) forms a daughter element (decay constant ${\lambda }_2$). The nuclear change will show radioactive equilibrium if :

[$T$ is average life]

• A. ${\lambda }_1>{\lambda }_2$
• B. ${\lambda }_1<{\lambda }_2$
• C. $T_2>T_1$
• D. $T_1>T_2$

Answer 1

Answer: (B), (D)

The correct options are
B ${\lambda }_1<{\lambda }_2$
D $T_1>T_2$

Daughter element will show equilibrium if it has a higher rate of decay means ${\lambda }_1<{\lambda }_2$.

As we know,

$T_{avg}=\frac{1}{\lambda }$ so radioactive equilibrium will be obtained when

$T_1>T_2$

Hence, option B and D are correct.