A park $80 m$ by $65 m$ has a $3 m$ wide track all around it. A wall has been constructed around the track leaving a space for gate which is $2 m$ . What is the length of the outer boundary leaving the gate which has a wall? Find the perimeter of the park without track.

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Solution

Length of outer boundary leaving the gate $= (3 + 65 + 3) + (3 + 80 + 3) + (3 + 65 + 3) + (3 + 80 - 2 + 3)$

$= 71 + 86 + 71 + 84$

$= 312 m$

Perimeter of park $= 2 \times (65 + 80)$

$= 290 m$

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A park 80 m by 65 m has a 3 m wide track all around it. A wall has been constructed around the track leaving a space for gate which is 2 m. What is the length of the outer boundary leaving the gate which has a wall? Find the perimeter of the park without track.

Length of outer boundary leaving the gate =(3+65+3)+(3+80+3)+(3+65+3)+(3+80−2+3)=71+86+71+84=312mPerimeter of park =2×(65+80)=290m

A park $80 m$ by $65 m$ has a $3 m$ wide track all around it. A wall has been constructed around the track leaving a space for gate which is $2 m$ . What is the length of the outer boundary leaving the gate which has a wall? Find the perimeter of the park without track.

Length of outer boundary leaving the gate $= (3 + 65 + 3) + (3 + 80 + 3) + (3 + 65 + 3) + (3 + 80 - 2 + 3)$

$= 71 + 86 + 71 + 84$

$= 312 m$

Perimeter of park $= 2 \times (65 + 80)$

$= 290 m$