A part of a journey is covered in $1$ hour $40$ minutes at $75$ km/hr and the remaining part of it is covered in $2$ hours $50$ minutes at $60$ km/hr. Find the total length of the journey.

165

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295

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200

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250

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Solution

The correct option is B $295$ km
$s_{1} = 75$ km/hr
$t_{1} = 1$ hour $40$ min $= 1 \frac{2}{3}$ hr

$d_{1} = s_{1} \times t_{1} = 75 \times \frac{5}{3} = 125$ km
$s_{2} = 60$ km/hr
$t_{2} = 2$ hr $50$ min $= 2 \frac{5}{6}$ hr

$d_{2} = s_{2} \times t_{2} = 60 \times \frac{17}{6} = 170$ km

Total distance $= 125$ km + $170$ km $= 295$ km

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A part of a journey is covered in 1 hour 40 minutes at 75 km/hr and the remaining part of it is covered in 2 hours 50 minutes at 60 km/hr. Find the total length of the journey.

The correct option is B 295 kms1=75 km/hrt1=1hour 40 min =123 hrd1=s1×t1=75×53=125 kms2=60 km/hrt2=2hr 50 min =256hrd2=s2×t2=60×176=170kmTotal distance =125 km + 170 km =295 km

A part of a journey is covered in $1$ hour $40$ minutes at $75$ km/hr and the remaining part of it is covered in $2$ hours $50$ minutes at $60$ km/hr. Find the total length of the journey.