i) Let the fixed monthly hostel charges be Rs.x
and the cost of food per day taken from the mess be y As per the given condition,
x+25y=3500 ...(1)
x+28y=3800 ...(2)
Subtracting eq(1) from eq (2), we get
3y=300
y=100
Substitute
y=100
in eq (1), we get
x+25(100)=3500
x+2500=3500
x=1000 So, the fixed monthly hostel charge is Rs.2500
and the cost of food per day is Rs. 100