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Question

A particle A having a charge of 2×106 C and a mass of 100 g is fixed at the bottom of a smooth inclined plane of inclination 30. Where should another particle B having same charge and mass be placed from bottom on the inclined plane so that B may remain in equilibrium ?

A
8 cm
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B
13 cm
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C
21 cm
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D
27 cm
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Solution

The correct option is D 27 cm

From equilibrium of forces,
Fe=mg sin 30
kq2r2=mg sin 30
r=kq2mg sin 30
r=  9×109×(2×106)2100×103×10×12
r=0.268 m0.27 m27 cm

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